Base | Representation |
---|---|
bin | 10100011100100010100… |
… | …001001010000100101111 |
3 | 11222022122012021011222112 |
4 | 110130202201022010233 |
5 | 141010002024020101 |
6 | 2553244034234235 |
7 | 203340016021061 |
oct | 24344241120457 |
9 | 4868565234875 |
10 | 1405033423151 |
11 | 4a1964813636 |
12 | 1a837aa2597b |
13 | a2656668877 |
14 | 4c00accb731 |
15 | 26834eb96bb |
hex | 1472284a12f |
1405033423151 has 4 divisors (see below), whose sum is σ = 1407494077704. Its totient is φ = 1402572768600.
The previous prime is 1405033423133. The next prime is 1405033423159. The reversal of 1405033423151 is 1513243305041.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1405033423151 - 238 = 1130155516207 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1405033423159) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1230326420 + ... + 1230327561.
It is an arithmetic number, because the mean of its divisors is an integer number (351873519426).
Almost surely, 21405033423151 is an apocalyptic number.
1405033423151 is a deficient number, since it is larger than the sum of its proper divisors (2460654553).
1405033423151 is an equidigital number, since it uses as much as digits as its factorization.
1405033423151 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2460654552.
The product of its (nonzero) digits is 21600, while the sum is 32.
Adding to 1405033423151 its reverse (1513243305041), we get a palindrome (2918276728192).
The spelling of 1405033423151 in words is "one trillion, four hundred five billion, thirty-three million, four hundred twenty-three thousand, one hundred fifty-one".
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