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140550322335 = 3567139851067
BaseRepresentation
bin1000001011100101110…
…0111011100010011111
3111102210012020011001220
42002321130323202133
54300321340303320
6144322401104423
713103653012413
oct2027134734237
9442705204056
10140550322335
1154674aa1495
12232a6028113
131033b8b6107
146b34762d43
1539c91c9e40
hex20b973b89f

140550322335 has 16 divisors (see below), whose sum is σ = 228236942976. Its totient is φ = 73841362848.

The previous prime is 140550322303. The next prime is 140550322379. The reversal of 140550322335 is 533223055041.

It is not a de Polignac number, because 140550322335 - 25 = 140550322303 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 140550322296 and 140550322305.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 69924529 + ... + 69926538.

It is an arithmetic number, because the mean of its divisors is an integer number (14264808936).

Almost surely, 2140550322335 is an apocalyptic number.

140550322335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

140550322335 is a deficient number, since it is larger than the sum of its proper divisors (87686620641).

140550322335 is a wasteful number, since it uses less digits than its factorization.

140550322335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 139851142.

The product of its (nonzero) digits is 54000, while the sum is 33.

Adding to 140550322335 its reverse (533223055041), we get a palindrome (673773377376).

The spelling of 140550322335 in words is "one hundred forty billion, five hundred fifty million, three hundred twenty-two thousand, three hundred thirty-five".

Divisors: 1 3 5 15 67 201 335 1005 139851067 419553201 699255335 2097766005 9370021489 28110064467 46850107445 140550322335