Base | Representation |
---|---|
bin | 11010010000111010… |
… | …00010010101110001 |
3 | 1100101200112020220012 |
4 | 31020131002111301 |
5 | 212334210120301 |
6 | 10251102024305 |
7 | 1006265021213 |
oct | 151035022561 |
9 | 40350466805 |
10 | 14100473201 |
11 | 5a86393241 |
12 | 2896278095 |
13 | 1439389b89 |
14 | 97a98c5b3 |
15 | 577d7cebb |
hex | 348742571 |
14100473201 has 2 divisors, whose sum is σ = 14100473202. Its totient is φ = 14100473200.
The previous prime is 14100473137. The next prime is 14100473203. The reversal of 14100473201 is 10237400141.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 14095388176 + 5085025 = 118724^2 + 2255^2 .
It is an emirp because it is prime and its reverse (10237400141) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 14100473201 - 26 = 14100473137 is a prime.
Together with 14100473203, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (14100473203) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7050236600 + 7050236601.
It is an arithmetic number, because the mean of its divisors is an integer number (7050236601).
Almost surely, 214100473201 is an apocalyptic number.
It is an amenable number.
14100473201 is a deficient number, since it is larger than the sum of its proper divisors (1).
14100473201 is an equidigital number, since it uses as much as digits as its factorization.
14100473201 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 672, while the sum is 23.
Adding to 14100473201 its reverse (10237400141), we get a palindrome (24337873342).
The spelling of 14100473201 in words is "fourteen billion, one hundred million, four hundred seventy-three thousand, two hundred one".
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