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14101155115401 = 34700385038467
BaseRepresentation
bin1100110100110010111001…
…0101110111000110001001
31211221001112202010020110010
43031030232111313012021
53322013131202143101
645553551540142133
72653526524553334
oct315145625670611
954831482106403
1014101155115401
1145472a24a0012
1216b8a94397949
137b396bb70c13
1436a6dca9761b
15196c0b7592d6
hexcd32e577189

14101155115401 has 4 divisors (see below), whose sum is σ = 18801540153872. Its totient is φ = 9400770076932.

The previous prime is 14101155115379. The next prime is 14101155115403. The reversal of 14101155115401 is 10451155110141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 14101155115401 - 227 = 14101020897673 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is not an unprimeable number, because it can be changed into a prime (14101155115403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2350192519231 + ... + 2350192519236.

It is an arithmetic number, because the mean of its divisors is an integer number (4700385038468).

Almost surely, 214101155115401 is an apocalyptic number.

It is an amenable number.

14101155115401 is a deficient number, since it is larger than the sum of its proper divisors (4700385038471).

14101155115401 is an equidigital number, since it uses as much as digits as its factorization.

14101155115401 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4700385038470.

The product of its (nonzero) digits is 2000, while the sum is 30.

The spelling of 14101155115401 in words is "fourteen trillion, one hundred one billion, one hundred fifty-five million, one hundred fifteen thousand, four hundred one".

Divisors: 1 3 4700385038467 14101155115401