Base | Representation |
---|---|
bin | 11010010001001111… |
… | …10100110101001011 |
3 | 1100101212211221112012 |
4 | 31020213310311023 |
5 | 212340421121301 |
6 | 10251242410135 |
7 | 1006331040641 |
oct | 151047646513 |
9 | 40355757465 |
10 | 14103301451 |
11 | 5a87a45138 |
12 | 289720094b |
13 | 1439b3a2b5 |
14 | 97b0c7191 |
15 | 57823aebb |
hex | 3489f4d4b |
14103301451 has 2 divisors, whose sum is σ = 14103301452. Its totient is φ = 14103301450.
The previous prime is 14103301427. The next prime is 14103301453. The reversal of 14103301451 is 15410330141.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 14103301451 - 222 = 14099107147 is a prime.
It is a super-2 number, since 2×141033014512 (a number of 21 digits) contains 22 as substring.
Together with 14103301453, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (14103301453) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7051650725 + 7051650726.
It is an arithmetic number, because the mean of its divisors is an integer number (7051650726).
Almost surely, 214103301451 is an apocalyptic number.
14103301451 is a deficient number, since it is larger than the sum of its proper divisors (1).
14103301451 is an equidigital number, since it uses as much as digits as its factorization.
14103301451 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 720, while the sum is 23.
Adding to 14103301451 its reverse (15410330141), we get a palindrome (29513631592).
The spelling of 14103301451 in words is "fourteen billion, one hundred three million, three hundred one thousand, four hundred fifty-one".
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