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14104232141 is a prime number
BaseRepresentation
bin11010010001010110…
…11000000011001101
31100101221121020012012
431020223120003031
5212341140412031
610251314351005
71006341665216
oct151053300315
940357536165
1014104232141
115a885203aa
12289758b465
13143a0a4abc
1497b28a40d
15578371b2b
hex348ad80cd

14104232141 has 2 divisors, whose sum is σ = 14104232142. Its totient is φ = 14104232140.

The previous prime is 14104232089. The next prime is 14104232143. The reversal of 14104232141 is 14123240141.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9717819241 + 4386412900 = 98579^2 + 66230^2 .

It is a cyclic number.

It is not a de Polignac number, because 14104232141 - 214 = 14104215757 is a prime.

Together with 14104232143, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14104232143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7052116070 + 7052116071.

It is an arithmetic number, because the mean of its divisors is an integer number (7052116071).

Almost surely, 214104232141 is an apocalyptic number.

It is an amenable number.

14104232141 is a deficient number, since it is larger than the sum of its proper divisors (1).

14104232141 is an equidigital number, since it uses as much as digits as its factorization.

14104232141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 14104232141 its reverse (14123240141), we get a palindrome (28227472282).

The spelling of 14104232141 in words is "fourteen billion, one hundred four million, two hundred thirty-two thousand, one hundred forty-one".