Base | Representation |
---|---|
bin | 11010010001010110… |
… | …11000000011001101 |
3 | 1100101221121020012012 |
4 | 31020223120003031 |
5 | 212341140412031 |
6 | 10251314351005 |
7 | 1006341665216 |
oct | 151053300315 |
9 | 40357536165 |
10 | 14104232141 |
11 | 5a885203aa |
12 | 289758b465 |
13 | 143a0a4abc |
14 | 97b28a40d |
15 | 578371b2b |
hex | 348ad80cd |
14104232141 has 2 divisors, whose sum is σ = 14104232142. Its totient is φ = 14104232140.
The previous prime is 14104232089. The next prime is 14104232143. The reversal of 14104232141 is 14123240141.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9717819241 + 4386412900 = 98579^2 + 66230^2 .
It is a cyclic number.
It is not a de Polignac number, because 14104232141 - 214 = 14104215757 is a prime.
Together with 14104232143, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14104232143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7052116070 + 7052116071.
It is an arithmetic number, because the mean of its divisors is an integer number (7052116071).
Almost surely, 214104232141 is an apocalyptic number.
It is an amenable number.
14104232141 is a deficient number, since it is larger than the sum of its proper divisors (1).
14104232141 is an equidigital number, since it uses as much as digits as its factorization.
14104232141 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 768, while the sum is 23.
Adding to 14104232141 its reverse (14123240141), we get a palindrome (28227472282).
The spelling of 14104232141 in words is "fourteen billion, one hundred four million, two hundred thirty-two thousand, one hundred forty-one".
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