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141100633405 = 5179157654339
BaseRepresentation
bin1000001101101001000…
…0001100110100111101
3111111012112201211221101
42003122100030310331
54302433230232110
6144453140133101
713123414411024
oct2033220146475
9444175654841
10141100633405
11549276a1326
122341a397191
13103c8905074
146b878938bb
153a0c68013a
hex20da40cd3d

141100633405 has 8 divisors (see below), whose sum is σ = 170266687200. Its totient is φ = 112249888656.

The previous prime is 141100633379. The next prime is 141100633409. The reversal of 141100633405 is 504336001141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 141100633405 - 213 = 141100625213 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141100633409) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 78826275 + ... + 78828064.

It is an arithmetic number, because the mean of its divisors is an integer number (21283335900).

Almost surely, 2141100633405 is an apocalyptic number.

It is an amenable number.

141100633405 is a deficient number, since it is larger than the sum of its proper divisors (29166053795).

141100633405 is a wasteful number, since it uses less digits than its factorization.

141100633405 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 157654523.

The product of its (nonzero) digits is 4320, while the sum is 28.

Adding to 141100633405 its reverse (504336001141), we get a palindrome (645436634546).

The spelling of 141100633405 in words is "one hundred forty-one billion, one hundred million, six hundred thirty-three thousand, four hundred five".

Divisors: 1 5 179 895 157654339 788271695 28220126681 141100633405