141103115 has 4 divisors (see below), whose sum is σ = 169323744. Its totient is φ = 112882488.

The previous prime is 141103097. The next prime is 141103121. The reversal of 141103115 is 511301141.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 511301141 = 13 ⋅39330857.

It is a cyclic number.

It is not a de Polignac number, because 141103115 - 2⁶ = 141103051 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 141103093 and 141103102.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 14110307 + ... + 14110316.

It is an arithmetic number, because the mean of its divisors is an integer number (42330936).

Almost surely, 2^141103115 is an apocalyptic number.

141103115 is a deficient number, since it is larger than the sum of its proper divisors (28220629).

141103115 is an equidigital number, since it uses as much as digits as its factorization.

141103115 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28220628.

The product of its (nonzero) digits is 60, while the sum is 17.

The square root of 141103115 is about 11878.6832182696. The cubic root of 141103115 is about 520.6096338684.

Adding to 141103115 its reverse (511301141), we get a palindrome (652404256).

The spelling of 141103115 in words is "one hundred forty-one million, one hundred three thousand, one hundred fifteen".