Base | Representation |
---|---|
bin | 1100110101010101011000… |
… | …0110100100011100111111 |
3 | 1211221221102212211022100210 |
4 | 3031111112012210130333 |
5 | 3322141111001130421 |
6 | 50002122302123503 |
7 | 2654305111103403 |
oct | 315252606443477 |
9 | 54857385738323 |
10 | 14110412130111 |
11 | 45502128761a0 |
12 | 16ba838580593 |
13 | 7b47b594b70b |
14 | 36ad3a293103 |
15 | 19709e2a3576 |
hex | cd5561a473f |
14110412130111 has 64 divisors (see below), whose sum is σ = 21460643366400. Its totient is φ = 8170287206400.
The previous prime is 14110412130083. The next prime is 14110412130119. The reversal of 14110412130111 is 11103121401141.
It is not a de Polignac number, because 14110412130111 - 217 = 14110411999039 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14110412130119) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 63355195 + ... + 63577523.
It is an arithmetic number, because the mean of its divisors is an integer number (335322552600).
Almost surely, 214110412130111 is an apocalyptic number.
14110412130111 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
14110412130111 is a deficient number, since it is larger than the sum of its proper divisors (7350231236289).
14110412130111 is a wasteful number, since it uses less digits than its factorization.
14110412130111 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 223320.
The product of its (nonzero) digits is 96, while the sum is 21.
Adding to 14110412130111 its reverse (11103121401141), we get a palindrome (25213533531252).
The spelling of 14110412130111 in words is "fourteen trillion, one hundred ten billion, four hundred twelve million, one hundred thirty thousand, one hundred eleven".
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