1411132115111 has 2 divisors, whose sum is σ = 1411132115112. Its totient is φ = 1411132115110.

The previous prime is 1411132115093. The next prime is 1411132115231. The reversal of 1411132115111 is 1115112311141.

It is a m-pointer prime, because the next prime (1411132115231) can be obtained adding 1411132115111 to its product of digits (120).

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1411132115111 is a prime.

It is a Sophie Germain prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1411132118111) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705566057555 + 705566057556.

It is an arithmetic number, because the mean of its divisors is an integer number (705566057556).

Almost surely, 2^{1411132115111} is an apocalyptic number.

1411132115111 is a deficient number, since it is larger than the sum of its proper divisors (1).

1411132115111 is an equidigital number, since it uses as much as digits as its factorization.

1411132115111 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 120, while the sum is 23.

Adding to 1411132115111 its reverse (1115112311141), we get a palindrome (2526244426252).

The spelling of 1411132115111 in words is "one trillion, four hundred eleven billion, one hundred thirty-two million, one hundred fifteen thousand, one hundred eleven".