Base | Representation |
---|---|
bin | 1100110101011011110111… |
… | …1100000101010011100000 |
3 | 1211222002221021212012211122 |
4 | 3031112331330011103200 |
5 | 3322203142434232202 |
6 | 50003011213031412 |
7 | 2654366223413135 |
oct | 315267574052340 |
9 | 54862837765748 |
10 | 14112154211552 |
11 | 4550a27170821 |
12 | 16bb043a85568 |
13 | 7b4a02840037 |
14 | 36b0637b058c |
15 | 1971521ba9a2 |
hex | cd5bdf054e0 |
14112154211552 has 24 divisors (see below), whose sum is σ = 27839888774712. Its totient is φ = 7041706268800.
The previous prime is 14112154211539. The next prime is 14112154211581. The reversal of 14112154211552 is 25511245121141.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 449072699 + ... + 449104122.
It is an arithmetic number, because the mean of its divisors is an integer number (1159995365613).
Almost surely, 214112154211552 is an apocalyptic number.
It is an amenable number.
14112154211552 is a deficient number, since it is larger than the sum of its proper divisors (13727734563160).
14112154211552 is an equidigital number, since it uses as much as digits as its factorization.
14112154211552 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 898177322 (or 898177314 counting only the distinct ones).
The product of its digits is 16000, while the sum is 35.
Adding to 14112154211552 its reverse (25511245121141), we get a palindrome (39623399332693).
The spelling of 14112154211552 in words is "fourteen trillion, one hundred twelve billion, one hundred fifty-four million, two hundred eleven thousand, five hundred fifty-two".
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