Base | Representation |
---|---|
bin | 100000000101101000001101… |
… | …001101011011000111001100 |
3 | 200111200100101010012100100112 |
4 | 200011220031031123013030 |
5 | 121444134434300102300 |
6 | 1220051331053015152 |
7 | 41503614435305312 |
oct | 4005501515330714 |
9 | 614610333170315 |
10 | 141124257034700 |
11 | 40a6a508aa3455 |
12 | 139b29b01844b8 |
13 | 6098c63b1b634 |
14 | 26bc6441bc0b2 |
15 | 114ae74801e35 |
hex | 805a0d35b1cc |
141124257034700 has 36 divisors (see below), whose sum is σ = 306304396592040. Its totient is φ = 56437765703040.
The previous prime is 141124257034699. The next prime is 141124257034703. The reversal of 141124257034700 is 7430752421141.
It is not an unprimeable number, because it can be changed into a prime (141124257034703) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 148738622 + ... + 149684421.
It is an arithmetic number, because the mean of its divisors is an integer number (8508455460890).
Almost surely, 2141124257034700 is an apocalyptic number.
141124257034700 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
141124257034700 is an abundant number, since it is smaller than the sum of its proper divisors (165180139557340).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
141124257034700 is a wasteful number, since it uses less digits than its factorization.
141124257034700 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 298427786 (or 298427779 counting only the distinct ones).
The product of its (nonzero) digits is 188160, while the sum is 41.
The spelling of 141124257034700 in words is "one hundred forty-one trillion, one hundred twenty-four billion, two hundred fifty-seven million, thirty-four thousand, seven hundred".
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