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141125124551135 = 5175916046063053
BaseRepresentation
bin100000000101101001000000…
…111010101111000111011111
3200111200102121120120202011212
4200011221000322233013133
5121444143223341114020
61220051553122535035
741503645101132614
oct4005510072570737
9614612546522155
10141125124551135
1140a6a91375938a
12139b2bb280747b
13609907178077a
1426bc6c74c050b
15114aec5a63cc5
hex805a40eaf1df

141125124551135 has 8 divisors (see below), whose sum is σ = 169446425850240. Its totient is φ = 112835915381664.

The previous prime is 141125124551129. The next prime is 141125124551167. The reversal of 141125124551135 is 531155421521141.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 141125124551135 - 236 = 141056405074399 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 141125124551092 and 141125124551101.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 8023022732 + ... + 8023040321.

It is an arithmetic number, because the mean of its divisors is an integer number (21180803231280).

Almost surely, 2141125124551135 is an apocalyptic number.

141125124551135 is a deficient number, since it is larger than the sum of its proper divisors (28321301299105).

141125124551135 is a wasteful number, since it uses less digits than its factorization.

141125124551135 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 16046064817.

The product of its digits is 120000, while the sum is 41.

The spelling of 141125124551135 in words is "one hundred forty-one trillion, one hundred twenty-five billion, one hundred twenty-four million, five hundred fifty-one thousand, one hundred thirty-five".

Divisors: 1 5 1759 8795 16046063053 80230315265 28225024910227 141125124551135