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14113004213412 = 223313172349095237
BaseRepresentation
bin1100110101011111000010…
…0110100101010010100100
31211222012010112021210012000
43031113300212211102210
53322211413034312122
650003231415325300
72654426254332516
oct315276046452244
954865115253160
1014113004213412
114551322a537a5
1216bb240680830
137b4b0997c110
1436b104633bb6
151971a1b1d0ac
hexcd5f09a54a4

14113004213412 has 384 divisors, whose sum is σ = 43552872115200. Its totient is φ = 3907784466432.

The previous prime is 14113004213411. The next prime is 14113004213431. The reversal of 14113004213412 is 21431240031141.

It is a happy number.

14113004213412 is a `hidden beast` number, since 1 + 4 + 1 + 1 + 30 + 0 + 4 + 213 + 412 = 666.

It is a Harshad number since it is a multiple of its sum of digits (27).

It is not an unprimeable number, because it can be changed into a prime (14113004213411) by changing a digit.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 2694861658 + ... + 2694866894.

It is an arithmetic number, because the mean of its divisors is an integer number (113418937800).

Almost surely, 214113004213412 is an apocalyptic number.

14113004213412 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 14113004213412, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (21776436057600).

14113004213412 is an abundant number, since it is smaller than the sum of its proper divisors (29439867901788).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14113004213412 is a wasteful number, since it uses less digits than its factorization.

14113004213412 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10212 (or 10204 counting only the distinct ones).

The product of its (nonzero) digits is 2304, while the sum is 27.

Adding to 14113004213412 its reverse (21431240031141), we get a palindrome (35544244244553).

The spelling of 14113004213412 in words is "fourteen trillion, one hundred thirteen billion, four million, two hundred thirteen thousand, four hundred twelve".