Search a number
-
+
14113005054150 = 2352495718980573
BaseRepresentation
bin1100110101011111000010…
…1001110010100011000110
31211222012010120212111110110
43031113300221302203012
53322211413243213100
650003231445333450
72654426264433612
oct315276051624306
954865116774413
1014113005054150
114551323478422
1216bb240a07286
137b4b09bb49b2
1436b1047b2342
151971a1c37250
hexcd5f0a728c6

14113005054150 has 48 divisors (see below), whose sum is σ = 35007315151824. Its totient is φ = 3762708593280.

The previous prime is 14113005054149. The next prime is 14113005054151. The reversal of 14113005054150 is 5145050031141.

14113005054150 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (14113005054149) and next prime (14113005054151).

It is a Harshad number since it is a multiple of its sum of digits (30).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14113005054151) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 8746737 + ... + 10233836.

It is an arithmetic number, because the mean of its divisors is an integer number (729319065663).

Almost surely, 214113005054150 is an apocalyptic number.

14113005054150 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

14113005054150 is an abundant number, since it is smaller than the sum of its proper divisors (20894310097674).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14113005054150 is a wasteful number, since it uses less digits than its factorization.

14113005054150 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 18985545 (or 18985540 counting only the distinct ones).

The product of its (nonzero) digits is 6000, while the sum is 30.

Adding to 14113005054150 its reverse (5145050031141), we get a palindrome (19258055085291).

The spelling of 14113005054150 in words is "fourteen trillion, one hundred thirteen billion, five million, fifty-four thousand, one hundred fifty".

Divisors: 1 2 3 5 6 10 15 25 30 50 75 150 4957 9914 14871 24785 29742 49570 74355 123925 148710 247850 371775 743550 18980573 37961146 56941719 94902865 113883438 189805730 284708595 474514325 569417190 949028650 1423542975 2847085950 94086700361 188173400722 282260101083 470433501805 564520202166 940867003610 1411300505415 2352167509025 2822601010830 4704335018050 7056502527075 14113005054150