1411310233103 has 4 divisors (see below), whose sum is σ = 1459976103240. Its totient is φ = 1362644362968.

The previous prime is 1411310233097. The next prime is 1411310233117. The reversal of 1411310233103 is 3013320131141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1411310233103 is a prime.

It is a super-2 number, since 2×1411310233103² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1411310233703) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24332935025 + ... + 24332935082.

It is an arithmetic number, because the mean of its divisors is an integer number (364994025810).

Almost surely, 2^{1411310233103} is an apocalyptic number.

1411310233103 is a deficient number, since it is larger than the sum of its proper divisors (48665870137).

1411310233103 is an equidigital number, since it uses as much as digits as its factorization.

1411310233103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 48665870136.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 1411310233103 its reverse (3013320131141), we get a palindrome (4424630364244).

The spelling of 1411310233103 in words is "one trillion, four hundred eleven billion, three hundred ten million, two hundred thirty-three thousand, one hundred three".