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141131134240021 is a prime number
BaseRepresentation
bin100000000101101110100111…
…000111111000010100010101
3200111201000010101212120111201
4200011232213013320110111
5121444243030331140041
61220054425323232501
741504250033503512
oct4005564707702425
9614630111776451
10141131134240021
1140a72417aa7612
12139b41ab378731
1360997bb85c5b3
1426bcad76d2309
15114b228462631
hex805ba71f8515

141131134240021 has 2 divisors, whose sum is σ = 141131134240022. Its totient is φ = 141131134240020.

The previous prime is 141131134240013. The next prime is 141131134240093. The reversal of 141131134240021 is 120042431131141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 86035104311121 + 55096029928900 = 9275511^2 + 7422670^2 .

It is a cyclic number.

It is not a de Polignac number, because 141131134240021 - 23 = 141131134240013 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141131134240121) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70565567120010 + 70565567120011.

It is an arithmetic number, because the mean of its divisors is an integer number (70565567120011).

Almost surely, 2141131134240021 is an apocalyptic number.

It is an amenable number.

141131134240021 is a deficient number, since it is larger than the sum of its proper divisors (1).

141131134240021 is an equidigital number, since it uses as much as digits as its factorization.

141131134240021 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2304, while the sum is 28.

Adding to 141131134240021 its reverse (120042431131141), we get a palindrome (261173565371162).

The spelling of 141131134240021 in words is "one hundred forty-one trillion, one hundred thirty-one billion, one hundred thirty-four million, two hundred forty thousand, twenty-one".