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141131134240093 is a prime number
BaseRepresentation
bin100000000101101110100111…
…000111111000010101011101
3200111201000010101212120121101
4200011232213013320111131
5121444243030331140333
61220054425323233101
741504250033503644
oct4005564707702535
9614630111776541
10141131134240093
1140a72417aa7678
12139b41ab378791
1360997bb85c63a
1426bcad76d235b
15114b22846267d
hex805ba71f855d

141131134240093 has 2 divisors, whose sum is σ = 141131134240094. Its totient is φ = 141131134240092.

The previous prime is 141131134240021. The next prime is 141131134240121. The reversal of 141131134240093 is 390042431131141.

141131134240093 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 88707351097764 + 52423783142329 = 9418458^2 + 7240427^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-141131134240093 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141131134240013) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70565567120046 + 70565567120047.

It is an arithmetic number, because the mean of its divisors is an integer number (70565567120047).

Almost surely, 2141131134240093 is an apocalyptic number.

It is an amenable number.

141131134240093 is a deficient number, since it is larger than the sum of its proper divisors (1).

141131134240093 is an equidigital number, since it uses as much as digits as its factorization.

141131134240093 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 31104, while the sum is 37.

The spelling of 141131134240093 in words is "one hundred forty-one trillion, one hundred thirty-one billion, one hundred thirty-four million, two hundred forty thousand, ninety-three".