141131200044340 has 24 divisors (see below), whose sum is σ = 323318749192992. Its totient is φ = 51320436379680.

The previous prime is 141131200044271. The next prime is 141131200044371. The reversal of 141131200044340 is 43440002131141.

It is a junction number, because it is equal to n+sod(n) for n = 141131200044299 and 141131200044308.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 320752727154 + ... + 320752727593.

It is an arithmetic number, because the mean of its divisors is an integer number (13471614549708).

Almost surely, 2^{141131200044340} is an apocalyptic number.

141131200044340 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

141131200044340 is an abundant number, since it is smaller than the sum of its proper divisors (182187549148652).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

141131200044340 is a wasteful number, since it uses less digits than its factorization.

141131200044340 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 641505454767 (or 641505454765 counting only the distinct ones).

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 141131200044340 its reverse (43440002131141), we get a palindrome (184571202175481).

The spelling of 141131200044340 in words is "one hundred forty-one trillion, one hundred thirty-one billion, two hundred million, forty-four thousand, three hundred forty".