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141131407 = 281502247
BaseRepresentation
bin10000110100101…
…11111010001111
3100211120012220011
420122113322033
5242112201112
622000534051
73332411554
oct1032277217
9324505804
10141131407
117273512a
123b321327
1323315311
1414a5aa2b
15c5cbaa7
hex8697e8f

141131407 has 4 divisors (see below), whose sum is σ = 141633936. Its totient is φ = 140628880.

The previous prime is 141131377. The next prime is 141131423. The reversal of 141131407 is 704131141.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 704131141 = 7100590163.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-141131407 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141131477) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 250843 + ... + 251404.

It is an arithmetic number, because the mean of its divisors is an integer number (35408484).

Almost surely, 2141131407 is an apocalyptic number.

141131407 is a deficient number, since it is larger than the sum of its proper divisors (502529).

141131407 is an equidigital number, since it uses as much as digits as its factorization.

141131407 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 502528.

The product of its (nonzero) digits is 336, while the sum is 22.

The square root of 141131407 is about 11879.8740313187. The cubic root of 141131407 is about 520.6444266355.

Adding to 141131407 its reverse (704131141), we get a palindrome (845262548).

The spelling of 141131407 in words is "one hundred forty-one million, one hundred thirty-one thousand, four hundred seven".

Divisors: 1 281 502247 141131407