1411321213 has 2 divisors, whose sum is σ = 1411321214. Its totient is φ = 1411321212.

The previous prime is 1411321211. The next prime is 1411321231. The reversal of 1411321213 is 3121231141.

Together with next prime (1411321231) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1355565124 + 55756089 = 36818^2 + 7467^2 .

It is a cyclic number.

It is not a de Polignac number, because 1411321213 - 2¹ = 1411321211 is a prime.

It is a super-3 number, since 3×1411321213³ (a number of 28 digits) contains 333 as substring.

Together with 1411321211, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1411321211) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 705660606 + 705660607.

It is an arithmetic number, because the mean of its divisors is an integer number (705660607).

Almost surely, 2^1411321213 is an apocalyptic number.

It is an amenable number.

1411321213 is a deficient number, since it is larger than the sum of its proper divisors (1).

1411321213 is an equidigital number, since it uses as much as digits as its factorization.

1411321213 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 144, while the sum is 19.

The square root of 1411321213 is about 37567.5553237098. Note that the first 3 decimals coincide. The cubic root of 1411321213 is about 1121.6963063005.

Adding to 1411321213 its reverse (3121231141), we get a palindrome (4532552354).

It can be divided in two parts, 1411 and 321213, that added together give a square (322624 = 568²).

The spelling of 1411321213 in words is "one billion, four hundred eleven million, three hundred twenty-one thousand, two hundred thirteen".