14113213040150 has 48 divisors (see below), whose sum is σ = 30074010125280. Its totient is φ = 4826985004800.

The previous prime is 14113213040117. The next prime is 14113213040159. The reversal of 14113213040150 is 5104031231141.

It is a super-3 number, since 3×14113213040150³ (a number of 40 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14113213040159) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 49152041 + ... + 49438340.

It is an arithmetic number, because the mean of its divisors is an integer number (626541877610).

Almost surely, 2^{14113213040150} is an apocalyptic number.

14113213040150 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

14113213040150 is an abundant number, since it is smaller than the sum of its proper divisors (15960797085130).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

14113213040150 is a wasteful number, since it uses less digits than its factorization.

14113213040150 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 98590809 (or 98590804 counting only the distinct ones).

The product of its (nonzero) digits is 1440, while the sum is 26.

Adding to 14113213040150 its reverse (5104031231141), we get a palindrome (19217244271291).

The spelling of 14113213040150 in words is "fourteen trillion, one hundred thirteen billion, two hundred thirteen million, forty thousand, one hundred fifty".