14113300331141 has 4 divisors (see below), whose sum is σ = 15396327633984. Its totient is φ = 12830273028300.

The previous prime is 14113300331131. The next prime is 14113300331149.

14113300331141 is nontrivially palindromic in base 10.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-14113300331141 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 14113300331141.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14113300331149) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 641513651405 + ... + 641513651426.

It is an arithmetic number, because the mean of its divisors is an integer number (3849081908496).

Almost surely, 2^{14113300331141} is an apocalyptic number.

14113300331141 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

14113300331141 is a deficient number, since it is larger than the sum of its proper divisors (1283027302843).

14113300331141 is a wasteful number, since it uses less digits than its factorization.

14113300331141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1283027302842.

The product of its (nonzero) digits is 1296, while the sum is 26.

It can be divided in two parts, 14113300 and 331141, that added together give a palindrome (14444441).

The spelling of 14113300331141 in words is "fourteen trillion, one hundred thirteen billion, three hundred million, three hundred thirty-one thousand, one hundred forty-one".