141134111 has 4 divisors (see below), whose sum is σ = 141157872. Its totient is φ = 141110352.

The previous prime is 141134107. The next prime is 141134131. The reversal of 141134111 is 111431141.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length, and also an emirpimes, since its reverse is a distinct semiprime: 111431141 = 17 ⋅6554773.

It is a cyclic number.

It is not a de Polignac number, because 141134111 - 2² = 141134107 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 141134111.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141134131) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5915 + ... + 17811.

It is an arithmetic number, because the mean of its divisors is an integer number (35289468).

Almost surely, 2^141134111 is an apocalyptic number.

141134111 is a deficient number, since it is larger than the sum of its proper divisors (23761).

141134111 is a wasteful number, since it uses less digits than its factorization.

141134111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 23760.

The product of its digits is 48, while the sum is 17.

The square root of 141134111 is about 11879.9878366941. The cubic root of 141134111 is about 520.6477517010.

Adding to 141134111 its reverse (111431141), we get a palindrome (252565252).

The spelling of 141134111 in words is "one hundred forty-one million, one hundred thirty-four thousand, one hundred eleven".