Base | Representation |
---|---|
bin | 1100110101100000101111… |
… | …0110100111111001100000 |
3 | 1211222020022101120102201022 |
4 | 3031120023312213321200 |
5 | 3322213332104400412 |
6 | 50003345030425012 |
7 | 2654443505355452 |
oct | 315301366477140 |
9 | 54866271512638 |
10 | 14113461403232 |
11 | 4551538030224 |
12 | 16bb349802168 |
13 | 7b4b805c5539 |
14 | 36b1492442d2 |
15 | 1971cbd2ba72 |
hex | cd60bda7e60 |
14113461403232 has 24 divisors (see below), whose sum is σ = 27789443120376. Its totient is φ = 7055825055232.
The previous prime is 14113461403169. The next prime is 14113461403243. The reversal of 14113461403232 is 23230416431141.
It is a junction number, because it is equal to n+sod(n) for n = 14113461403192 and 14113461403201.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28048178 + ... + 28546929.
It is an arithmetic number, because the mean of its divisors is an integer number (1157893463349).
Almost surely, 214113461403232 is an apocalyptic number.
It is an amenable number.
14113461403232 is a deficient number, since it is larger than the sum of its proper divisors (13675981717144).
14113461403232 is an equidigital number, since it uses as much as digits as its factorization.
14113461403232 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 56602910 (or 56602902 counting only the distinct ones).
The product of its (nonzero) digits is 41472, while the sum is 35.
Adding to 14113461403232 its reverse (23230416431141), we get a palindrome (37343877834373).
The spelling of 14113461403232 in words is "fourteen trillion, one hundred thirteen billion, four hundred sixty-one million, four hundred three thousand, two hundred thirty-two".
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