Base | Representation |
---|---|
bin | 11010010010101011… |
… | …00110010001100111 |
3 | 1100102201102120001202 |
4 | 31021111212101213 |
5 | 212402004103310 |
6 | 10252351513115 |
7 | 1006535034314 |
oct | 151125462147 |
9 | 40381376052 |
10 | 14115300455 |
11 | 5a937a0173 |
12 | 289b22879b |
13 | 143c47b9b9 |
14 | 97c92bd0b |
15 | 57930b3a5 |
hex | 349566467 |
14115300455 has 8 divisors (see below), whose sum is σ = 16941197952. Its totient is φ = 11290348768.
The previous prime is 14115300449. The next prime is 14115300473. The reversal of 14115300455 is 55400351141.
14115300455 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 14115300455 - 26 = 14115300391 is a prime.
It is a Duffinian number.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 203192 + ... + 263661.
It is an arithmetic number, because the mean of its divisors is an integer number (2117649744).
Almost surely, 214115300455 is an apocalyptic number.
14115300455 is a deficient number, since it is larger than the sum of its proper divisors (2825897497).
14115300455 is an equidigital number, since it uses as much as digits as its factorization.
14115300455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 472905.
The product of its (nonzero) digits is 6000, while the sum is 29.
Adding to 14115300455 its reverse (55400351141), we get a palindrome (69515651596).
The spelling of 14115300455 in words is "fourteen billion, one hundred fifteen million, three hundred thousand, four hundred fifty-five".
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