14115401303 has 4 divisors (see below), whose sum is σ = 14177040840. Its totient is φ = 14053761768.

The previous prime is 14115401273. The next prime is 14115401309. The reversal of 14115401303 is 30310451141.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 30310451141 = 421 ⋅71996321.

It is a cyclic number.

It is not a de Polignac number, because 14115401303 - 2¹⁰ = 14115400279 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14115401309) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30819425 + ... + 30819882.

It is an arithmetic number, because the mean of its divisors is an integer number (3544260210).

Almost surely, 2^14115401303 is an apocalyptic number.

14115401303 is a deficient number, since it is larger than the sum of its proper divisors (61639537).

14115401303 is an equidigital number, since it uses as much as digits as its factorization.

14115401303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 61639536.

The product of its (nonzero) digits is 720, while the sum is 23.

Adding to 14115401303 its reverse (30310451141), we get a palindrome (44425852444).

The spelling of 14115401303 in words is "fourteen billion, one hundred fifteen million, four hundred one thousand, three hundred three".