Base | Representation |
---|---|
bin | 11010010011010000… |
… | …10111100111000000 |
3 | 1100110001200112221121 |
4 | 31021220113213000 |
5 | 212404234033440 |
6 | 10253045202024 |
7 | 1006624620265 |
oct | 151150274700 |
9 | 40401615847 |
10 | 14120221120 |
11 | 5a96551135 |
12 | 28a0a00314 |
13 | 14404b2635 |
14 | 97d44d26c |
15 | 57997e34a |
hex | 349a179c0 |
14120221120 has 28 divisors (see below), whose sum is σ = 33623777304. Its totient is φ = 5648088320.
The previous prime is 14120221043. The next prime is 14120221153. The reversal of 14120221120 is 2112202141.
It is a Harshad number since it is a multiple of its sum of digits (16).
It is a junction number, because it is equal to n+sod(n) for n = 14120221094 and 14120221103.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 22062526 + ... + 22063165.
Almost surely, 214120221120 is an apocalyptic number.
14120221120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
14120221120 is an abundant number, since it is smaller than the sum of its proper divisors (19503556184).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14120221120 is an equidigital number, since it uses as much as digits as its factorization.
14120221120 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 44125708 (or 44125698 counting only the distinct ones).
The product of its (nonzero) digits is 64, while the sum is 16.
Adding to 14120221120 its reverse (2112202141), we get a palindrome (16232423261).
The spelling of 14120221120 in words is "fourteen billion, one hundred twenty million, two hundred twenty-one thousand, one hundred twenty".
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