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14120243132014 = 27060121566007
BaseRepresentation
bin1100110101111010000000…
…0100110111011001101110
31211222212211000120221200101
43031132200010313121232
53322321224220211024
650010430010421314
72655103534201465
oct315364004673156
954885730527611
1014120243132014
1145543a8152458
121700720a3183a
137b56c16178c6
1436b5cdbc39dc
151974773ccc44
hexcd7a013766e

14120243132014 has 4 divisors (see below), whose sum is σ = 21180364698024. Its totient is φ = 7060121566006.

The previous prime is 14120243131997. The next prime is 14120243132033. The reversal of 14120243132014 is 41023134202141.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a super-2 number, since 2×141202431320142 (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3530060783002 + ... + 3530060783005.

It is an arithmetic number, because the mean of its divisors is an integer number (5295091174506).

Almost surely, 214120243132014 is an apocalyptic number.

14120243132014 is a deficient number, since it is larger than the sum of its proper divisors (7060121566010).

14120243132014 is an equidigital number, since it uses as much as digits as its factorization.

14120243132014 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 7060121566009.

The product of its (nonzero) digits is 4608, while the sum is 28.

Adding to 14120243132014 its reverse (41023134202141), we get a palindrome (55143377334155).

The spelling of 14120243132014 in words is "fourteen trillion, one hundred twenty billion, two hundred forty-three million, one hundred thirty-two thousand, fourteen".

Divisors: 1 2 7060121566007 14120243132014