Base | Representation |
---|---|
bin | 11010010011010001… |
… | …10010101101010011 |
3 | 1100110001220012012112 |
4 | 31021220302231103 |
5 | 212404301111430 |
6 | 10253051415535 |
7 | 1006625562011 |
oct | 151150625523 |
9 | 40401805175 |
10 | 14120332115 |
11 | 5a9661756a |
12 | 28a0a545ab |
13 | 1440521006 |
14 | 97d47b8b1 |
15 | 5799a2195 |
hex | 349a32b53 |
14120332115 has 4 divisors (see below), whose sum is σ = 16944398544. Its totient is φ = 11296265688.
The previous prime is 14120332103. The next prime is 14120332159. The reversal of 14120332115 is 51123302141.
14120332115 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 14120332115 - 232 = 9825364819 is a prime.
It is a Duffinian number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1412033207 + ... + 1412033216.
It is an arithmetic number, because the mean of its divisors is an integer number (4236099636).
Almost surely, 214120332115 is an apocalyptic number.
14120332115 is a deficient number, since it is larger than the sum of its proper divisors (2824066429).
14120332115 is an equidigital number, since it uses as much as digits as its factorization.
14120332115 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2824066428.
The product of its (nonzero) digits is 720, while the sum is 23.
Adding to 14120332115 its reverse (51123302141), we get a palindrome (65243634256).
The spelling of 14120332115 in words is "fourteen billion, one hundred twenty million, three hundred thirty-two thousand, one hundred fifteen".
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