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1412104564500 = 223537270127407
BaseRepresentation
bin10100100011000111111…
…111011010111100010100
311222222212222212101100120
4110203013333122330110
5141113442232031000
63000413433311540
7204010160516400
oct24430777327424
94888788771316
101412104564500
114a4963238803
121a9812b655b0
13a321261c986
144c4bc086100
1526aeab876a0
hex148c7fdaf14

1412104564500 has 288 divisors, whose sum is σ = 4790401814016. Its totient is φ = 322294560000.

The previous prime is 1412104564483. The next prime is 1412104564501. The reversal of 1412104564500 is 54654012141.

It is a super-3 number, since 3×14121045645003 (a number of 37 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1412104564501) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 51509797 + ... + 51537203.

It is an arithmetic number, because the mean of its divisors is an integer number (16633339632).

Almost surely, 21412104564500 is an apocalyptic number.

1412104564500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1412104564500, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (2395200907008).

1412104564500 is an abundant number, since it is smaller than the sum of its proper divisors (3378297249516).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1412104564500 is a wasteful number, since it uses less digits than its factorization.

1412104564500 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 28144 (or 28125 counting only the distinct ones).

The product of its (nonzero) digits is 19200, while the sum is 33.

Adding to 1412104564500 its reverse (54654012141), we get a palindrome (1466758576641).

The spelling of 1412104564500 in words is "one trillion, four hundred twelve billion, one hundred four million, five hundred sixty-four thousand, five hundred".