1412211010031 has 4 divisors (see below), whose sum is σ = 1473611488752. Its totient is φ = 1350810531312.

The previous prime is 1412211010013. The next prime is 1412211010109. The reversal of 1412211010031 is 1300101122141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1412211010031 - 2²² = 1412206815727 is a prime.

It is a super-2 number, since 2×1412211010031² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1412211009991 and 1412211010009.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1412211010531) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30700239326 + ... + 30700239371.

It is an arithmetic number, because the mean of its divisors is an integer number (368402872188).

Almost surely, 2^{1412211010031} is an apocalyptic number.

1412211010031 is a deficient number, since it is larger than the sum of its proper divisors (61400478721).

1412211010031 is an equidigital number, since it uses as much as digits as its factorization.

1412211010031 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 61400478720.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 1412211010031 its reverse (1300101122141), we get a palindrome (2712312132172).

The spelling of 1412211010031 in words is "one trillion, four hundred twelve billion, two hundred eleven million, ten thousand, thirty-one".