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1412222221303 is a prime number
BaseRepresentation
bin10100100011001111000…
…000001111101111110111
312000000012012020222010221
4110203033000033233313
5141114212342040203
63000433235155211
7204013116551215
oct24431700175767
95000165228127
101412222221303
114a4a1369a033
121a9846445b07
13a3230b0619a
144c4cd951cb5
1526b06178abd
hex148cf00fbf7

1412222221303 has 2 divisors, whose sum is σ = 1412222221304. Its totient is φ = 1412222221302.

The previous prime is 1412222221301. The next prime is 1412222221309. The reversal of 1412222221303 is 3031222222141.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1412222221303 - 21 = 1412222221301 is a prime.

Together with 1412222221301, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1412222221301) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 706111110651 + 706111110652.

It is an arithmetic number, because the mean of its divisors is an integer number (706111110652).

Almost surely, 21412222221303 is an apocalyptic number.

1412222221303 is a deficient number, since it is larger than the sum of its proper divisors (1).

1412222221303 is an equidigital number, since it uses as much as digits as its factorization.

1412222221303 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 1412222221303 its reverse (3031222222141), we get a palindrome (4443444443444).

The spelling of 1412222221303 in words is "one trillion, four hundred twelve billion, two hundred twenty-two million, two hundred twenty-one thousand, three hundred three".