14122411303 has 48 divisors (see below), whose sum is σ = 19257548800. Its totient is φ = 10076996160.

The previous prime is 14122411253. The next prime is 14122411319. The reversal of 14122411303 is 30311422141.

14122411303 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not a de Polignac number, because 14122411303 - 2¹³ = 14122403111 is a prime.

It is a super-3 number, since 3×14122411303³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14122411393) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 1393348 + ... + 1403446.

Almost surely, 2^14122411303 is an apocalyptic number.

14122411303 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

14122411303 is a deficient number, since it is larger than the sum of its proper divisors (5135137497).

14122411303 is a wasteful number, since it uses less digits than its factorization.

14122411303 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 10268 (or 10257 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 14122411303 its reverse (30311422141), we get a palindrome (44433833444).

The spelling of 14122411303 in words is "fourteen billion, one hundred twenty-two million, four hundred eleven thousand, three hundred three".