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1412400213104 = 2488275013319
BaseRepresentation
bin10100100011011001100…
…111001110110001110000
312000000122121011212222212
4110203121213032301300
5141120043423304404
63000503034151252
7204020410503566
oct24433147166160
95000577155885
101412400213104
114a4aa510a9a1
121a9895b82528
13a325b955c8a
144c509445a36
1526b16ad706e
hex148d99cec70

1412400213104 has 10 divisors (see below), whose sum is σ = 2736525412920. Its totient is φ = 706200106544.

The previous prime is 1412400213079. The next prime is 1412400213127. The reversal of 1412400213104 is 4013120042141.

It is a super-2 number, since 2×14124002131042 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1412400213104.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 44137506644 + ... + 44137506675.

It is an arithmetic number, because the mean of its divisors is an integer number (273652541292).

Almost surely, 21412400213104 is an apocalyptic number.

It is an amenable number.

1412400213104 is a deficient number, since it is larger than the sum of its proper divisors (1324125199816).

1412400213104 is an equidigital number, since it uses as much as digits as its factorization.

1412400213104 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 88275013327 (or 88275013321 counting only the distinct ones).

The product of its (nonzero) digits is 768, while the sum is 23.

Adding to 1412400213104 its reverse (4013120042141), we get a palindrome (5425520255245).

The spelling of 1412400213104 in words is "one trillion, four hundred twelve billion, four hundred million, two hundred thirteen thousand, one hundred four".

Divisors: 1 2 4 8 16 88275013319 176550026638 353100053276 706200106552 1412400213104