Base | Representation |
---|---|
bin | 10100100011011100000… |
… | …010110111101100111111 |
3 | 12000000202102221202000011 |
4 | 110203130002313230333 |
5 | 141120134344404210 |
6 | 3000511052444051 |
7 | 204021414343102 |
oct | 24433402675477 |
9 | 5000672852004 |
10 | 1412441013055 |
11 | 4a5016147566 |
12 | 1a98a7779627 |
13 | a326723c967 |
14 | 4c510a26739 |
15 | 26b1a495d8a |
hex | 148dc0b7b3f |
1412441013055 has 16 divisors (see below), whose sum is σ = 1727448197760. Its totient is φ = 1108286802688.
The previous prime is 1412441013047. The next prime is 1412441013059. The reversal of 1412441013055 is 5503101442141.
It is a cyclic number.
It is not a de Polignac number, because 1412441013055 - 23 = 1412441013047 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1412441013059) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 19914 + ... + 1680856.
It is an arithmetic number, because the mean of its divisors is an integer number (107965512360).
Almost surely, 21412441013055 is an apocalyptic number.
1412441013055 is a deficient number, since it is larger than the sum of its proper divisors (315007184705).
1412441013055 is a wasteful number, since it uses less digits than its factorization.
1412441013055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1664210.
The product of its (nonzero) digits is 9600, while the sum is 31.
Adding to 1412441013055 its reverse (5503101442141), we get a palindrome (6915542455196).
The spelling of 1412441013055 in words is "one trillion, four hundred twelve billion, four hundred forty-one million, thirteen thousand, fifty-five".
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