14125001132311 has 4 divisors (see below), whose sum is σ = 14131161187432. Its totient is φ = 14118841077192.

The previous prime is 14125001132293. The next prime is 14125001132317. The reversal of 14125001132311 is 11323110052141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 14125001132311 - 2⁵ = 14125001132279 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (14125001132317) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3080024121 + ... + 3080028706.

It is an arithmetic number, because the mean of its divisors is an integer number (3532790296858).

Almost surely, 2^{14125001132311} is an apocalyptic number.

14125001132311 is a deficient number, since it is larger than the sum of its proper divisors (6160055121).

14125001132311 is an equidigital number, since it uses as much as digits as its factorization.

14125001132311 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6160055120.

The product of its (nonzero) digits is 720, while the sum is 25.

Adding to 14125001132311 its reverse (11323110052141), we get a palindrome (25448111184452).

The spelling of 14125001132311 in words is "fourteen trillion, one hundred twenty-five billion, one million, one hundred thirty-two thousand, three hundred eleven".