Base | Representation |
---|---|
bin | 1100110110001011101110… |
… | …1011001100100100011000 |
3 | 1212000100002121121102001122 |
4 | 3031202323223030210120 |
5 | 3322411000242213222 |
6 | 50012534055104412 |
7 | 2655332460424460 |
oct | 315427353144430 |
9 | 55010077542048 |
10 | 14125001132312 |
11 | 45564199a0504 |
12 | 170162a372108 |
13 | 7b5c9c2a53b5 |
14 | 36b921a8cba0 |
15 | 197654e80a42 |
hex | cd8bbacc918 |
14125001132312 has 16 divisors (see below), whose sum is σ = 30267859569360. Its totient is φ = 6053571913824.
The previous prime is 14125001132293. The next prime is 14125001132317. The reversal of 14125001132312 is 21323110052141.
14125001132312 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (14125001132317) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 126116081483 + ... + 126116081594.
It is an arithmetic number, because the mean of its divisors is an integer number (1891741223085).
Almost surely, 214125001132312 is an apocalyptic number.
It is an amenable number.
14125001132312 is an abundant number, since it is smaller than the sum of its proper divisors (16142858437048).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
14125001132312 is a wasteful number, since it uses less digits than its factorization.
14125001132312 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 252232163090 (or 252232163086 counting only the distinct ones).
The product of its (nonzero) digits is 1440, while the sum is 26.
Adding to 14125001132312 its reverse (21323110052141), we get a palindrome (35448111184453).
The spelling of 14125001132312 in words is "fourteen trillion, one hundred twenty-five billion, one million, one hundred thirty-two thousand, three hundred twelve".
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