Base | Representation |
---|---|
bin | 100000000111011101101001… |
… | …110001110000000011001100 |
3 | 200112010101212201220200110212 |
4 | 200013131221301300003030 |
5 | 122003221221203104400 |
6 | 1220225304345221552 |
7 | 41516000461632104 |
oct | 4007355161600314 |
9 | 615111781820425 |
10 | 141250364113100 |
11 | 41008a41174a00 |
12 | 13a133251918b8 |
13 | 60a7b10323058 |
14 | 26c47a8648204 |
15 | 114e3a59e2335 |
hex | 807769c700cc |
141250364113100 has 108 divisors (see below), whose sum is σ = 341526527825112. Its totient is φ = 50660155180800.
The previous prime is 141250364113051. The next prime is 141250364113193. The reversal of 141250364113100 is 1311463052141.
141250364113100 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a super-2 number, since 2×1412503641131002 (a number of 29 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 79072754 + ... + 80839353.
Almost surely, 2141250364113100 is an apocalyptic number.
141250364113100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
141250364113100 is an abundant number, since it is smaller than the sum of its proper divisors (200276163712012).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
141250364113100 is a wasteful number, since it uses less digits than its factorization.
141250364113100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 159912216 (or 159912198 counting only the distinct ones).
The product of its (nonzero) digits is 8640, while the sum is 32.
The spelling of 141250364113100 in words is "one hundred forty-one trillion, two hundred fifty billion, three hundred sixty-four million, one hundred thirteen thousand, one hundred".
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