141305135021301 has 4 divisors (see below), whose sum is σ = 188406846695072. Its totient is φ = 94203423347532.

The previous prime is 141305135021299. The next prime is 141305135021339. The reversal of 141305135021301 is 103120531503141.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 141305135021301 - 2¹ = 141305135021299 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141305135021381) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23550855836881 + ... + 23550855836886.

It is an arithmetic number, because the mean of its divisors is an integer number (47101711673768).

Almost surely, 2^{141305135021301} is an apocalyptic number.

It is an amenable number.

141305135021301 is a deficient number, since it is larger than the sum of its proper divisors (47101711673771).

141305135021301 is an equidigital number, since it uses as much as digits as its factorization.

141305135021301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 47101711673770.

The product of its (nonzero) digits is 5400, while the sum is 30.

Adding to 141305135021301 its reverse (103120531503141), we get a palindrome (244425666524442).

The spelling of 141305135021301 in words is "one hundred forty-one trillion, three hundred five billion, one hundred thirty-five million, twenty-one thousand, three hundred one".