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141311427116887 is a prime number
BaseRepresentation
bin100000001000010110100001…
…011010100111111101010111
3200112100020111022201200021201
4200020112201122213331113
5122010221300320220022
61220313323505253331
741523261616615156
oct4010264132477527
9615306438650251
10141311427116887
1141031926698495
1213a23127034247
1360b07c2079661
1426c771c36959d
151150c7b71e127
hex8085a16a7f57

141311427116887 has 2 divisors, whose sum is σ = 141311427116888. Its totient is φ = 141311427116886.

The previous prime is 141311427116837. The next prime is 141311427116921. The reversal of 141311427116887 is 788611724113141.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 141311427116887 - 211 = 141311427114839 is a prime.

It is a super-2 number, since 2×1413114271168872 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141311427116807) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70655713558443 + 70655713558444.

It is an arithmetic number, because the mean of its divisors is an integer number (70655713558444).

Almost surely, 2141311427116887 is an apocalyptic number.

141311427116887 is a deficient number, since it is larger than the sum of its proper divisors (1).

141311427116887 is an equidigital number, since it uses as much as digits as its factorization.

141311427116887 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 1806336, while the sum is 55.

The spelling of 141311427116887 in words is "one hundred forty-one trillion, three hundred eleven billion, four hundred twenty-seven million, one hundred sixteen thousand, eight hundred eighty-seven".