141311431311207 has 4 divisors (see below), whose sum is σ = 188415241748280. Its totient is φ = 94207620874136.

The previous prime is 141311431311191. The next prime is 141311431311227. The reversal of 141311431311207 is 702113134113141.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 141311431311207 - 2⁴ = 141311431311191 is a prime.

It is a super-2 number, since 2×141311431311207² (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141311431311227) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23551905218532 + ... + 23551905218537.

It is an arithmetic number, because the mean of its divisors is an integer number (47103810437070).

Almost surely, 2^{141311431311207} is an apocalyptic number.

141311431311207 is a deficient number, since it is larger than the sum of its proper divisors (47103810437073).

141311431311207 is an equidigital number, since it uses as much as digits as its factorization.

141311431311207 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 47103810437072.

The product of its (nonzero) digits is 6048, while the sum is 33.

Adding to 141311431311207 its reverse (702113134113141), we get a palindrome (843424565424348).

The spelling of 141311431311207 in words is "one hundred forty-one trillion, three hundred eleven billion, four hundred thirty-one million, three hundred eleven thousand, two hundred seven".