141312000111 has 4 divisors (see below), whose sum is σ = 188416000152. Its totient is φ = 94208000072.

The previous prime is 141312000103. The next prime is 141312000113. The reversal of 141312000111 is 111000213141.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 111000213141 = 3 ⋅37000071047.

It is a cyclic number.

It is not a de Polignac number, because 141312000111 - 2³ = 141312000103 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (141312000113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 23552000016 + ... + 23552000021.

It is an arithmetic number, because the mean of its divisors is an integer number (47104000038).

Almost surely, 2^141312000111 is an apocalyptic number.

141312000111 is a deficient number, since it is larger than the sum of its proper divisors (47104000041).

141312000111 is an equidigital number, since it uses as much as digits as its factorization.

141312000111 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 47104000040.

The product of its (nonzero) digits is 24, while the sum is 15.

Adding to 141312000111 its reverse (111000213141), we get a palindrome (252312213252).

The spelling of 141312000111 in words is "one hundred forty-one billion, three hundred twelve million, one hundred eleven", and thus it is an aban number.