Base | Representation |
---|---|
bin | 11010010100101011… |
… | …11000011011011111 |
3 | 1100110220010201002012 |
4 | 31022111320123133 |
5 | 212420312331111 |
6 | 10254153021435 |
7 | 1010131211264 |
oct | 151225703337 |
9 | 40426121065 |
10 | 14132152031 |
11 | 5aa225aa98 |
12 | 28a49b487b |
13 | 1442acc04a |
14 | 980c7726b |
15 | 57aa3948b |
hex | 34a5786df |
14132152031 has 2 divisors, whose sum is σ = 14132152032. Its totient is φ = 14132152030.
The previous prime is 14132152019. The next prime is 14132152043. The reversal of 14132152031 is 13025123141.
It is a balanced prime because it is at equal distance from previous prime (14132152019) and next prime (14132152043).
It is a cyclic number.
It is not a de Polignac number, because 14132152031 - 26 = 14132151967 is a prime.
It is a super-2 number, since 2×141321520312 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 14132151988 and 14132152006.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (14132152091) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7066076015 + 7066076016.
It is an arithmetic number, because the mean of its divisors is an integer number (7066076016).
Almost surely, 214132152031 is an apocalyptic number.
14132152031 is a deficient number, since it is larger than the sum of its proper divisors (1).
14132152031 is an equidigital number, since it uses as much as digits as its factorization.
14132152031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 720, while the sum is 23.
Adding to 14132152031 its reverse (13025123141), we get a palindrome (27157275172).
The spelling of 14132152031 in words is "fourteen billion, one hundred thirty-two million, one hundred fifty-two thousand, thirty-one".
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