14132202431 has 2 divisors, whose sum is σ = 14132202432. Its totient is φ = 14132202430.

The previous prime is 14132202401. The next prime is 14132202433. The reversal of 14132202431 is 13420223141.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 14132202431 - 2²² = 14128008127 is a prime.

It is a super-2 number, since 2×14132202431² (a number of 21 digits) contains 22 as substring.

Together with 14132202433, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 14132202397 and 14132202406.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (14132202433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7066101215 + 7066101216.

It is an arithmetic number, because the mean of its divisors is an integer number (7066101216).

Almost surely, 2^14132202431 is an apocalyptic number.

14132202431 is a deficient number, since it is larger than the sum of its proper divisors (1).

14132202431 is an equidigital number, since it uses as much as digits as its factorization.

14132202431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 14132202431 its reverse (13420223141), we get a palindrome (27552425572).

The spelling of 14132202431 in words is "fourteen billion, one hundred thirty-two million, two hundred two thousand, four hundred thirty-one".