Base | Representation |
---|---|
bin | 1000001110011110010… |
… | …1111000011111110111 |
3 | 111111210010211102221221 |
4 | 2003213211320133313 |
5 | 4303413022433421 |
6 | 144531252451211 |
7 | 13132102521226 |
oct | 2034745703767 |
9 | 444703742857 |
10 | 141324421111 |
11 | 54a31a51345 |
12 | 23481319b07 |
13 | 1043309a823 |
14 | 6ba94a8cbd |
15 | 3a22137841 |
hex | 20e79787f7 |
141324421111 has 2 divisors, whose sum is σ = 141324421112. Its totient is φ = 141324421110.
The previous prime is 141324421109. The next prime is 141324421163. The reversal of 141324421111 is 111124423141.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 141324421111 - 21 = 141324421109 is a prime.
It is a super-3 number, since 3×1413244211113 (a number of 34 digits) contains 333 as substring.
Together with 141324421109, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (141324421171) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70662210555 + 70662210556.
It is an arithmetic number, because the mean of its divisors is an integer number (70662210556).
Almost surely, 2141324421111 is an apocalyptic number.
141324421111 is a deficient number, since it is larger than the sum of its proper divisors (1).
141324421111 is an equidigital number, since it uses as much as digits as its factorization.
141324421111 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 768, while the sum is 25.
Adding to 141324421111 its reverse (111124423141), we get a palindrome (252448844252).
The spelling of 141324421111 in words is "one hundred forty-one billion, three hundred twenty-four million, four hundred twenty-one thousand, one hundred eleven".
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