Base | Representation |
---|---|
bin | 100000001000101011101010… |
… | …000001111010011010000100 |
3 | 200112102102001211210100122121 |
4 | 200020223222001322122010 |
5 | 122011104234233241400 |
6 | 1220331555401135324 |
7 | 41525024153006464 |
oct | 4010535201723204 |
9 | 615372054710577 |
10 | 141334120212100 |
11 | 41040511317832 |
12 | 13a275baa8a544 |
13 | 60b299a690c4a |
14 | 26c88721a7ba4 |
15 | 1151658b0921a |
hex | 808aea07a684 |
141334120212100 has 36 divisors (see below), whose sum is σ = 322836885120400. Its totient is φ = 53558192921760.
The previous prime is 141334120212079. The next prime is 141334120212149. The reversal of 141334120212100 is 1212021433141.
It is a super-2 number, since 2×1413341202121002 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 37193187630 + ... + 37193191429.
Almost surely, 2141334120212100 is an apocalyptic number.
141334120212100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
141334120212100 is an abundant number, since it is smaller than the sum of its proper divisors (181502764908300).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
141334120212100 is a wasteful number, since it uses less digits than its factorization.
141334120212100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 74386379092 (or 74386379085 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 25.
Adding to 141334120212100 its reverse (1212021433141), we get a palindrome (142546141645241).
The spelling of 141334120212100 in words is "one hundred forty-one trillion, three hundred thirty-four billion, one hundred twenty million, two hundred twelve thousand, one hundred".
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