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141344015341 is a prime number
BaseRepresentation
bin1000001110100011000…
…0101000001111101101
3111111211111200221012011
42003220300220033231
54303433031442331
6144533232441221
713132431210244
oct2035060501755
9444744627164
10141344015341
1154a42014821
12234879a9211
131043716b349
146babd2995b
153a23c083b1
hex20e8c283ed

141344015341 has 2 divisors, whose sum is σ = 141344015342. Its totient is φ = 141344015340.

The previous prime is 141344015339. The next prime is 141344015347. The reversal of 141344015341 is 143510443141.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 117426155625 + 23917859716 = 342675^2 + 154654^2 .

It is a cyclic number.

It is not a de Polignac number, because 141344015341 - 21 = 141344015339 is a prime.

Together with 141344015339, it forms a pair of twin primes.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (141344015347) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 70672007670 + 70672007671.

It is an arithmetic number, because the mean of its divisors is an integer number (70672007671).

Almost surely, 2141344015341 is an apocalyptic number.

It is an amenable number.

141344015341 is a deficient number, since it is larger than the sum of its proper divisors (1).

141344015341 is an equidigital number, since it uses as much as digits as its factorization.

141344015341 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 11520, while the sum is 31.

Adding to 141344015341 its reverse (143510443141), we get a palindrome (284854458482).

The spelling of 141344015341 in words is "one hundred forty-one billion, three hundred forty-four million, fifteen thousand, three hundred forty-one".