1413441301 has 4 divisors (see below), whose sum is σ = 1415747692. Its totient is φ = 1411134912.

The previous prime is 1413441269. The next prime is 1413441317. The reversal of 1413441301 is 1031443141.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 1031443141 = 1297 ⋅795253.

It can be written as a sum of positive squares in 2 ways, for example, as 431559076 + 981882225 = 20774^2 + 31335^2 .

It is a cyclic number.

It is not a de Polignac number, because 1413441301 - 2⁵ = 1413441269 is a prime.

It is a super-2 number, since 2×1413441301² = 3995632622745145202, which contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1413441361) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1152276 + ... + 1153501.

It is an arithmetic number, because the mean of its divisors is an integer number (353936923).

Almost surely, 2^1413441301 is an apocalyptic number.

It is an amenable number.

1413441301 is a deficient number, since it is larger than the sum of its proper divisors (2306391).

1413441301 is an equidigital number, since it uses as much as digits as its factorization.

1413441301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2306390.

The product of its (nonzero) digits is 576, while the sum is 22.

The square root of 1413441301 is about 37595.7617425156. The cubic root of 1413441301 is about 1122.2576963553.

Adding to 1413441301 its reverse (1031443141), we get a palindrome (2444884442).

The spelling of 1413441301 in words is "one billion, four hundred thirteen million, four hundred forty-one thousand, three hundred one".