1414430625353 has 4 divisors (see below), whose sum is σ = 1475927609088. Its totient is φ = 1352933641620.

The previous prime is 1414430625341. The next prime is 1414430625373. The reversal of 1414430625353 is 3535260344141.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1414430625353 - 2³⁰ = 1413356883529 is a prime.

It is a super-2 number, since 2×1414430625353² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1414430625353.

It is not an unprimeable number, because it can be changed into a prime (1414430625373) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 30748491833 + ... + 30748491878.

It is an arithmetic number, because the mean of its divisors is an integer number (368981902272).

Almost surely, 2^{1414430625353} is an apocalyptic number.

It is an amenable number.

1414430625353 is a deficient number, since it is larger than the sum of its proper divisors (61496983735).

1414430625353 is an equidigital number, since it uses as much as digits as its factorization.

1414430625353 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 61496983734.

The product of its (nonzero) digits is 518400, while the sum is 41.

Adding to 1414430625353 its reverse (3535260344141), we get a palindrome (4949690969494).

The spelling of 1414430625353 in words is "one trillion, four hundred fourteen billion, four hundred thirty million, six hundred twenty-five thousand, three hundred fifty-three".